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binary: append slices
A new optimization in Go 1.11 improves the efficiency of slice extension: "The compiler now optimizes slice extension of the form append(s, make([]T, n)...)." https://tip.golang.org/doc/go1.11#performance-compiler Before: BenchmarkMarshalUnmarshal-12 2000000 664 ns/op 0 B/op 0 allocs/op BenchmarkReadWrite-12 500000 2395 ns/op 304 B/op 24 allocs/op After: BenchmarkMarshalUnmarshal-12 2000000 628 ns/op 0 B/op 0 allocs/op BenchmarkReadWrite-12 500000 2411 ns/op 304 B/op 24 allocs/op BenchmarkMarshalUnmarshal benchmarks the code in this package, BenchmarkReadWrite benchmarks the code in the standard library. PiperOrigin-RevId: 209679979 Change-Id: I51c6302e53f60bf79f84576b1ead4d36658897cb
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+3
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@@ -35,21 +35,21 @@ var BigEndian = binary.BigEndian
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// AppendUint16 appends the binary representation of a uint16 to buf.
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func AppendUint16(buf []byte, order binary.ByteOrder, num uint16) []byte {
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buf = extendZero(2, buf)
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buf = append(buf, make([]byte, 2)...)
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order.PutUint16(buf[len(buf)-2:], num)
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return buf
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}
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// AppendUint32 appends the binary representation of a uint32 to buf.
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func AppendUint32(buf []byte, order binary.ByteOrder, num uint32) []byte {
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buf = extendZero(4, buf)
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buf = append(buf, make([]byte, 4)...)
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order.PutUint32(buf[len(buf)-4:], num)
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return buf
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}
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// AppendUint64 appends the binary representation of a uint64 to buf.
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func AppendUint64(buf []byte, order binary.ByteOrder, num uint64) []byte {
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buf = extendZero(8, buf)
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buf = append(buf, make([]byte, 8)...)
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order.PutUint64(buf[len(buf)-8:], num)
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return buf
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}
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@@ -204,13 +204,6 @@ func sizeof(data reflect.Value) uintptr {
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}
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}
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func extendZero(amount uintptr, buf []byte) []byte {
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for i := uintptr(0); i < amount; i++ {
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buf = append(buf, 0)
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}
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return buf
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}
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// ReadUint16 reads a uint16 from r.
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func ReadUint16(r io.Reader, order binary.ByteOrder) (uint16, error) {
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buf := make([]byte, 2)
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