configure: Do not ignore malloc value

Not checking the value of malloc will cause a warning with GCC 10.1,
which may result in configuration failure, with the following line in
config.log:

config-temp/qemu-conf.c:2:18: error: ignoring return value of ‘malloc’ declared with attribute ‘warn_unused_result’ [-Werror=unused-result]
    2 | int main(void) { malloc(1); return 0; }
      |                  ^~~~~~~~~

Signed-off-by: Leonid Bloch <lb.workbox@gmail.com>
Message-Id: <20200524221204.9791-1-lb.workbox@gmail.com>
Signed-off-by: Paolo Bonzini <pbonzini@redhat.com>
This commit is contained in:
Leonid Bloch
2020-06-10 12:10:50 -04:00
committed by Paolo Bonzini
parent c08790f48b
commit f2dfe54c74
Vendored
+17 -3
View File
@@ -4587,7 +4587,13 @@ fi
if test "$tcmalloc" = "yes" ; then
cat > $TMPC << EOF
#include <stdlib.h>
int main(void) { malloc(1); return 0; }
int main(void) {
void *tmp = malloc(1);
if (tmp != NULL) {
return 0;
}
return 1;
}
EOF
if compile_prog "" "-ltcmalloc" ; then
@@ -4603,7 +4609,13 @@ fi
if test "$jemalloc" = "yes" ; then
cat > $TMPC << EOF
#include <stdlib.h>
int main(void) { malloc(1); return 0; }
int main(void) {
void *tmp = malloc(1);
if (tmp != NULL) {
return 0;
}
return 1;
}
EOF
if compile_prog "" "-ljemalloc" ; then
@@ -6164,7 +6176,9 @@ if test "$sanitizers" = "yes" ; then
#include <stdlib.h>
int main(void) {
void *tmp = malloc(10);
return *(int *)(tmp + 2);
if (tmp != NULL) {
return *(int *)(tmp + 2);
}
}
EOF
if compile_prog "$CPU_CFLAGS -Werror -fsanitize=undefined" ""; then