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ppc/xive: Explicitly zero NSR after accepting
Have xive_tctx_accept clear NSR in one shot rather than masking out bits as they are tested, which makes it clear it's reset to 0, and does not have a partial NSR value in the register. Signed-off-by: Nicholas Piggin <npiggin@gmail.com> Reviewed-by: Glenn Miles <milesg@linux.ibm.com> Reviewed-by: Michael Kowal <kowal@linux.ibm.com> Reviewed-by: Caleb Schlossin <calebs@linux.ibm.com> Tested-by: Gautam Menghani <gautam@linux.ibm.com> Link: https://lore.kernel.org/qemu-devel/20250512031100.439842-15-npiggin@gmail.com Signed-off-by: Cédric Le Goater <clg@redhat.com>
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committed by
Cédric Le Goater
parent
14bcc5239f
commit
9d466ab9b6
+2
-4
@@ -68,13 +68,11 @@ static uint64_t xive_tctx_accept(XiveTCTX *tctx, uint8_t ring)
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* If the interrupt was for a specific VP, reset the pending
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* buffer bit, otherwise clear the logical server indicator
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*/
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if (regs[TM_NSR] & TM_NSR_GRP_LVL) {
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regs[TM_NSR] &= ~TM_NSR_GRP_LVL;
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} else {
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if (!(regs[TM_NSR] & TM_NSR_GRP_LVL)) {
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alt_regs[TM_IPB] &= ~xive_priority_to_ipb(cppr);
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}
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/* Drop the exception bit and any group/crowd */
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/* Clear the exception from NSR */
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regs[TM_NSR] = 0;
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trace_xive_tctx_accept(tctx->cs->cpu_index, alt_ring,
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