gecko/js/tests/ecma/String/15.5.4.7-1.js

220 lines
7.5 KiB
JavaScript

/* -*- Mode: C++; tab-width: 2; indent-tabs-mode: nil; c-basic-offset: 2 -*- */
/* ***** BEGIN LICENSE BLOCK *****
* Version: MPL 1.1/GPL 2.0/LGPL 2.1
*
* The contents of this file are subject to the Mozilla Public License Version
* 1.1 (the "License"); you may not use this file except in compliance with
* the License. You may obtain a copy of the License at
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*
* Software distributed under the License is distributed on an "AS IS" basis,
* WITHOUT WARRANTY OF ANY KIND, either express or implied. See the License
* for the specific language governing rights and limitations under the
* License.
*
* The Original Code is Mozilla Communicator client code, released
* March 31, 1998.
*
* The Initial Developer of the Original Code is
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* Portions created by the Initial Developer are Copyright (C) 1998
* the Initial Developer. All Rights Reserved.
*
* Contributor(s):
*
* Alternatively, the contents of this file may be used under the terms of
* either the GNU General Public License Version 2 or later (the "GPL"), or
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* ***** END LICENSE BLOCK ***** */
gTestfile = '15.5.4.7-1.js';
/**
File Name: 15.5.4.7-1.js
ECMA Section: 15.5.4.7 String.prototype.lastIndexOf( searchString, pos)
Description:
If the given searchString appears as a substring of the result of
converting this object to a string, at one or more positions that are
at or to the left of the specified position, then the index of the
rightmost such position is returned; otherwise -1 is returned. If position
is undefined or not supplied, the length of this string value is assumed,
so as to search all of the string.
When the lastIndexOf method is called with two arguments searchString and
position, the following steps are taken:
1.Call ToString, giving it the this value as its argument.
2.Call ToString(searchString).
3.Call ToNumber(position). (If position is undefined or not supplied, this step produces the value NaN).
4.If Result(3) is NaN, use +; otherwise, call ToInteger(Result(3)).
5.Compute the number of characters in Result(1).
6.Compute min(max(Result(4), 0), Result(5)).
7.Compute the number of characters in the string that is Result(2).
8.Compute the largest possible integer k not larger than Result(6) such that k+Result(7) is not greater
than Result(5), and for all nonnegative integers j less than Result(7), the character at position k+j of
Result(1) is the same as the character at position j of Result(2); but if there is no such integer k, then
compute the value -1.
1.Return Result(8).
Note that the lastIndexOf function is intentionally generic; it does not require that its this value be a
String object. Therefore it can be transferred to other kinds of objects for use as a method.
Author: christine@netscape.com
Date: 2 october 1997
*/
var SECTION = "15.5.4.7-1";
var VERSION = "ECMA_1";
startTest();
var TITLE = "String.protoype.lastIndexOf";
var TEST_STRING = new String( " !\"#$%&'()*+,-./0123456789:;<=>?@ABCDEFGHIJKLMNOPQRSTUVWXYZ[\\]^_`abcdefghijklmnopqrstuvwxyz{|}~" );
writeHeaderToLog( SECTION + " "+ TITLE);
var j = 0;
for ( k = 0, i = 0x0021; i < 0x007e; i++, j++, k++ ) {
new TestCase( SECTION,
"String.lastIndexOf(" +String.fromCharCode(i)+ ", 0)",
-1,
TEST_STRING.lastIndexOf( String.fromCharCode(i), 0 ) );
}
for ( k = 0, i = 0x0020; i < 0x007e; i++, j++, k++ ) {
new TestCase( SECTION,
"String.lastIndexOf("+String.fromCharCode(i)+ ", "+ k +")",
k,
TEST_STRING.lastIndexOf( String.fromCharCode(i), k ) );
}
for ( k = 0, i = 0x0020; i < 0x007e; i++, j++, k++ ) {
new TestCase( SECTION,
"String.lastIndexOf("+String.fromCharCode(i)+ ", "+k+1+")",
k,
TEST_STRING.lastIndexOf( String.fromCharCode(i), k+1 ) );
}
for ( k = 9, i = 0x0021; i < 0x007d; i++, j++, k++ ) {
new TestCase( SECTION,
"String.lastIndexOf("+(String.fromCharCode(i) +
String.fromCharCode(i+1)+
String.fromCharCode(i+2)) +", "+ 0 + ")",
LastIndexOf( TEST_STRING, String.fromCharCode(i) +
String.fromCharCode(i+1)+String.fromCharCode(i+2), 0),
TEST_STRING.lastIndexOf( (String.fromCharCode(i)+
String.fromCharCode(i+1)+
String.fromCharCode(i+2)),
0 ) );
}
for ( k = 0, i = 0x0020; i < 0x007d; i++, j++, k++ ) {
new TestCase( SECTION,
"String.lastIndexOf("+(String.fromCharCode(i) +
String.fromCharCode(i+1)+
String.fromCharCode(i+2)) +", "+ k +")",
k,
TEST_STRING.lastIndexOf( (String.fromCharCode(i)+
String.fromCharCode(i+1)+
String.fromCharCode(i+2)),
k ) );
}
for ( k = 0, i = 0x0020; i < 0x007d; i++, j++, k++ ) {
new TestCase( SECTION,
"String.lastIndexOf("+(String.fromCharCode(i) +
String.fromCharCode(i+1)+
String.fromCharCode(i+2)) +", "+ k+1 +")",
k,
TEST_STRING.lastIndexOf( (String.fromCharCode(i)+
String.fromCharCode(i+1)+
String.fromCharCode(i+2)),
k+1 ) );
}
for ( k = 0, i = 0x0020; i < 0x007d; i++, j++, k++ ) {
new TestCase( SECTION,
"String.lastIndexOf("+
(String.fromCharCode(i) +
String.fromCharCode(i+1)+
String.fromCharCode(i+2)) +", "+ (k-1) +")",
LastIndexOf( TEST_STRING, String.fromCharCode(i) +
String.fromCharCode(i+1)+String.fromCharCode(i+2), k-1),
TEST_STRING.lastIndexOf( (String.fromCharCode(i)+
String.fromCharCode(i+1)+
String.fromCharCode(i+2)),
k-1 ) );
}
new TestCase( SECTION, "String.lastIndexOf(" +TEST_STRING + ", 0 )", 0, TEST_STRING.lastIndexOf( TEST_STRING, 0 ) );
// new TestCase( SECTION, "String.lastIndexOf(" +TEST_STRING + ", 1 )", 0, TEST_STRING.lastIndexOf( TEST_STRING, 1 ));
new TestCase( SECTION, "String.lastIndexOf(" +TEST_STRING + ")", 0, TEST_STRING.lastIndexOf( TEST_STRING ));
print( "TEST_STRING = new String(\" !\"#$%&'()*+,-./0123456789:;<=>?@ABCDEFGHIJKLMNOPQRSTUVWXYZ[\\]^_`abcdefghijklmnopqrstuvwxyz{|}~\")" );
test();
function LastIndexOf( string, search, position ) {
string = String( string );
search = String( search );
position = Number( position )
if ( isNaN( position ) ) {
position = Infinity;
} else {
position = ToInteger( position );
}
result5= string.length;
result6 = Math.min(Math.max(position, 0), result5);
result7 = search.length;
if (result7 == 0) {
return Math.min(position, result5);
}
result8 = -1;
for ( k = 0; k <= result6; k++ ) {
if ( k+ result7 > result5 ) {
break;
}
for ( j = 0; j < result7; j++ ) {
if ( string.charAt(k+j) != search.charAt(j) ){
break;
} else {
if ( j == result7 -1 ) {
result8 = k;
}
}
}
}
return result8;
}
function ToInteger( n ) {
n = Number( n );
if ( isNaN(n) ) {
return 0;
}
if ( Math.abs(n) == 0 || Math.abs(n) == Infinity ) {
return n;
}
var sign = ( n < 0 ) ? -1 : 1;
return ( sign * Math.floor(Math.abs(n)) );
}