gecko/xpcom/tests/TestDeadlockDetectorScalability.cpp
2012-05-21 12:12:37 +01:00

191 lines
4.7 KiB
C++

/* -*- Mode: C++; tab-width: 4; indent-tabs-mode: nil; c-basic-offset: 4 -*-
* vim: sw=4 ts=4 et :
* This Source Code Form is subject to the terms of the Mozilla Public
* License, v. 2.0. If a copy of the MPL was not distributed with this
* file, You can obtain one at http://mozilla.org/MPL/2.0/. */
#include "TestHarness.h"
//#define OLD_API
#define PASS() \
do { \
passed(__FUNCTION__); \
return NS_OK; \
} while (0)
#define FAIL(why) \
do { \
fail("%s | %s - %s", __FILE__, __FUNCTION__, why); \
return NS_ERROR_FAILURE; \
} while (0)
#ifdef OLD_API
# include "nsAutoLock.h"
typedef PRLock* moz_lock_t;
# define NEWLOCK(n) nsAutoLock::NewLock(n)
# define DELETELOCK(v) nsAutoLock::DestroyLock(v)
# define AUTOLOCK(v, l) nsAutoLock v(l)
#else
# include "mozilla/Mutex.h"
typedef mozilla::Mutex* moz_lock_t;
# define NEWLOCK(n) new mozilla::Mutex(n)
# define DELETELOCK(v) delete (v)
# define AUTOLOCK(v, l) mozilla::MutexAutoLock v(*l)
#endif
// def/undef these to run particular tests.
#undef DD_TEST1
#undef DD_TEST2
#undef DD_TEST3
//-----------------------------------------------------------------------------
#ifdef DD_TEST1
static void
AllocLockRecurseUnlockFree(int i)
{
if (0 == i)
return;
moz_lock_t lock = NEWLOCK("deadlockDetector.scalability.t1");
{
AUTOLOCK(_, lock);
AllocLockRecurseUnlockFree(i - 1);
}
DELETELOCK(lock);
}
// This test creates a resource dependency chain N elements long, then
// frees all the resources in the chain.
static nsresult
LengthNDepChain(int N)
{
AllocLockRecurseUnlockFree(N);
PASS();
}
#endif
//-----------------------------------------------------------------------------
#ifdef DD_TEST2
// This test creates a single lock that is ordered < N resources, then
// repeatedly exercises this order k times.
static nsresult
OneLockNDeps(const int N, const int K)
{
moz_lock_t lock = NEWLOCK("deadlockDetector.scalability.t2.master");
moz_lock_t* locks = new moz_lock_t[N];
if (!locks)
NS_RUNTIMEABORT("couldn't allocate lock array");
for (int i = 0; i < N; ++i)
locks[i] =
NEWLOCK("deadlockDetector.scalability.t2.dep");
// establish orders
{AUTOLOCK(m, lock);
for (int i = 0; i < N; ++i)
AUTOLOCK(s, locks[i]);
}
// exercise order check
{AUTOLOCK(m, lock);
for (int i = 0; i < K; ++i)
for (int j = 0; j < N; ++j)
AUTOLOCK(s, locks[i]);
}
for (int i = 0; i < N; ++i)
DELETELOCK(locks[i]);
delete[] locks;
PASS();
}
#endif
//-----------------------------------------------------------------------------
#ifdef DD_TEST3
// This test creates N resources and adds the theoretical maximum number
// of dependencies, O(N^2). It then repeats that sequence of
// acquisitions k times. Finally, all resources are freed.
//
// It's very difficult to perform well on this test. It's put forth as a
// challenge problem.
static nsresult
MaxDepsNsq(const int N, const int K)
{
moz_lock_t* locks = new moz_lock_t[N];
if (!locks)
NS_RUNTIMEABORT("couldn't allocate lock array");
for (int i = 0; i < N; ++i)
locks[i] = NEWLOCK("deadlockDetector.scalability.t3");
for (int i = 0; i < N; ++i) {
AUTOLOCK(al1, locks[i]);
for (int j = i+1; j < N; ++j)
AUTOLOCK(al2, locks[j]);
}
for (int i = 0; i < K; ++i) {
for (int j = 0; j < N; ++j) {
AUTOLOCK(al1, locks[j]);
for (int k = j+1; k < N; ++k)
AUTOLOCK(al2, locks[k]);
}
}
for (int i = 0; i < N; ++i)
DELETELOCK(locks[i]);
delete[] locks;
PASS();
}
#endif
//-----------------------------------------------------------------------------
int
main(int argc, char** argv)
{
ScopedXPCOM xpcom("Deadlock detector scalability (" __FILE__ ")");
if (xpcom.failed())
return 1;
int rv = 0;
// Uncomment these tests to run them. Not expected to be common.
#ifndef DD_TEST1
puts("Skipping not-requested LengthNDepChain() test");
#else
if (NS_FAILED(LengthNDepChain(1 << 14))) // 16K
rv = 1;
#endif
#ifndef DD_TEST2
puts("Skipping not-requested OneLockNDeps() test");
#else
if (NS_FAILED(OneLockNDeps(1 << 14, 100))) // 16k
rv = 1;
#endif
#ifndef DD_TEST3
puts("Skipping not-requested MaxDepsNsq() test");
#else
if (NS_FAILED(MaxDepsNsq(1 << 10, 10))) // 1k
rv = 1;
#endif
return rv;
}