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Bug 1043144 - Don't write machc bytecode file; r=mshal
When writing bytecode, Python will append "c" to the loaded filename to produce a bytecode file. Since "mach" was being imported, this resulted in the creation of a "machc" file. The implementation of imp.load_module() in CPython's import.c checks sys.dont_write_bytecode. So, we wrap imp.load_module to set this flag when importing mach. --HG-- extra : rebase_source : 248a2349663affee3920a0726e10818d57c6ff17 extra : amend_source : 221280da9963cf91975658144ff3011353852fee
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parent
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17
mach
17
mach
@ -92,6 +92,7 @@ if __name__ == '__main__':
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def fork_interpose():
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import imp
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import os
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import sys
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orig_find_module = imp.find_module
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def my_find_module(name, dirs):
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if name == 'mach':
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@ -100,7 +101,23 @@ if __name__ == '__main__':
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return (f, path, ('', 'r', imp.PY_SOURCE))
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return orig_find_module(name, dirs)
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# Don't allow writing bytecode file for mach module.
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orig_load_module = imp.load_module
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def my_load_module(name, file, path, description):
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# multiprocess.forking invokes imp.load_module manually and
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# hard-codes the name __parents_main__ as the module name.
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if name == '__parents_main__':
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old_bytecode = sys.dont_write_bytecode
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sys.dont_write_bytecode = True
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try:
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return orig_load_module(name, file, path, description)
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finally:
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sys.dont_write_bytecode = old_bytecode
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return orig_load_module(name, file, path, description)
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imp.find_module = my_find_module
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imp.load_module = my_load_module
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from multiprocessing.forking import main; main()
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def my_get_command_line():
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