14 lines
201 B
C
14 lines
201 B
C
extern int g1, g2;
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extern void foo(int n);
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int main() {
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int i, j;
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for (i = 0; i < 1000; i++)
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for (j = 0; j < 1000; j++)
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foo(i * j);
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if (g2 - g1 == 280001)
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return 0;
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return 1;
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}
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