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sched/eevdf: Take into account current's lag when updating slice protection

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Take into account the lag of current task when updating the slice
protection in order to ensure that the absolute value of lags will remain
in the range [0 : slice+tick]
A task that already has a negative lag will see its protection reduced
whereas a task with positive lag will keep a full slice protection.

Signed-off-by: Vincent Guittot <vincent.guittot@linaro.org>
Signed-off-by: Peter Zijlstra (Intel) <peterz@infradead.org>
Tested-by: K Prateek Nayak <kprateek.nayak@amd.com>
Link: https://patch.msgid.link/20260624151229.1710703-3-vincent.guittot@linaro.org
This commit is contained in:
Vincent Guittot
2026-06-30 10:56:54 +02:00
committed by Peter Zijlstra
parent 8f97b627ff
commit 49f87b4d0b
1 changed files with 2 additions and 1 deletions
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kernel/sched/fair.c
+2 -1
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@@ -1067,8 +1067,9 @@ static inline void set_protect_slice(struct cfs_rq *cfs_rq, struct sched_entity
static inline void update_protect_slice(struct cfs_rq *cfs_rq, struct sched_entity *se)
{
u64 slice = cfs_rq_min_slice(cfs_rq);
u64 vruntime = min_vruntime(se->vruntime, avg_vruntime(cfs_rq));
se->vprot = min_vruntime(se->vprot, se->vruntime + calc_delta_fair(slice, se));
se->vprot = min_vruntime(se->vprot, vruntime + calc_delta_fair(slice, se));
}
static inline bool protect_slice(struct sched_entity *se)