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memory: expose alignment used for allocating RAM as MemoryRegion API

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introduce memory_region_get_alignment() that returns
underlying memory block alignment or 0 if it's not
relevant/implemented for backend.

Signed-off-by: Igor Mammedov <imammedo@redhat.com>
Reviewed-by: Michael S. Tsirkin <mst@redhat.com>
Signed-off-by: Michael S. Tsirkin <mst@redhat.com>
This commit is contained in:
Igor Mammedov
2014-11-23 12:11:30 +02:00
committed by Michael S. Tsirkin
parent 92a37a04d6
commit a2b257d621
8 changed files with 22 additions and 8 deletions
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include/exec/exec-all.h
+1 -1
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@@ -333,7 +333,7 @@ extern uintptr_t tci_tb_ptr;
#if !defined(CONFIG_USER_ONLY)
void phys_mem_set_alloc(void *(*alloc)(size_t));
void phys_mem_set_alloc(void *(*alloc)(size_t, uint64_t *align));
struct MemoryRegion *iotlb_to_region(AddressSpace *as, hwaddr index);
bool io_mem_read(struct MemoryRegion *mr, hwaddr addr,
include/exec/memory.h
+2
View File
@@ -146,6 +146,7 @@ struct MemoryRegion {
hwaddr addr;
void (*destructor)(MemoryRegion *mr);
ram_addr_t ram_addr;
uint64_t align;
bool subpage;
bool terminates;
bool romd_mode;
@@ -838,6 +839,7 @@ void memory_region_add_subregion_overlap(MemoryRegion *mr,
*/
ram_addr_t memory_region_get_ram_addr(MemoryRegion *mr);
uint64_t memory_region_get_alignment(const MemoryRegion *mr);
/**
* memory_region_del_subregion: Remove a subregion.
*