Files
why3/examples/binomial_heap.mlw
Mário dccef8ab6c No more let empty () = ... in examples.
We use now the more idiomatic `let empty = ...` expression.

TODO: port `queens_bv` example. After applying this change to the code,
I was able to reproduce the proof.
2020-09-10 18:13:14 +01:00

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(** Binomial heaps (Jean Vuillemin, 1978).
Purely applicative implementation, following Okasaki's implementation
in his book "Purely Functional Data Structures" (Section 3.2).
Author: Jean-Christophe Filliâtre (CNRS)
*)
module BinomialHeap
use int.Int
use list.List
use list.Length
use list.Reverse
use list.Append
(** The type of elements, together with a total pre-order *)
type elt
val predicate le elt elt
clone relations.TotalPreOrder with type t = elt, predicate rel = le, axiom .
(** Trees.
These are arbitrary trees, not yet constrained
to be binomial trees. Field `rank` is used later to store the rank
of the binomial tree, for access in constant time. *)
type tree = {
elem: elt;
children: list tree;
rank: int;
}
function size (l: list tree) : int =
match l with
| Nil -> 0
| Cons { children = c } r -> 1 + size c + size r
end
let lemma size_nonnneg (l: list tree)
ensures { size l >= 0 }
= let rec auxl (l: list tree) ensures { size l >= 0 } variant { l }
= match l with Nil -> () | Cons t r -> auxt t; auxl r end
with auxt (t: tree) ensures { size t.children >= 0 } variant { t }
= match t with { children = c } -> auxl c end in
auxl l
(** Heaps. *)
(* `e` is no greater than the roots of the trees in `l` *)
predicate le_roots (e: elt) (l: list tree) =
match l with
| Nil -> true
| Cons t r -> le e t.elem && le_roots e r
end
lemma le_roots_trans:
forall x y l. le x y -> le_roots y l -> le_roots x l
predicate heaps (l: list tree) =
match l with
| Nil -> true
| Cons { elem = e; children = c } r -> le_roots e c && heaps c && heaps r
end
lemma heaps_append:
forall h1 [@induction] h2. heaps h1 -> heaps h2 -> heaps (h1 ++ h2)
lemma heaps_reverse:
forall h. heaps h -> heaps (reverse h)
(** Number of occurrences of a given element in a list of trees. *)
function occ (x: elt) (l: list tree) : int =
match l with
| Nil -> 0
| Cons { elem = y; children = c } r ->
(if x = y then 1 else 0) + occ x c + occ x r
end
let rec lemma occ_nonneg (x: elt) (l: list tree)
variant { size l }
ensures { 0 <= occ x l }
= match l with
| Nil -> ()
| Cons { children = c } r -> occ_nonneg x c; occ_nonneg x r
end
lemma occ_append:
forall l1 [@induction] l2 x. occ x (l1 ++ l2) = occ x l1 + occ x l2
lemma occ_reverse:
forall x l. occ x l = occ x (reverse l)
predicate mem (x: elt) (l: list tree) =
occ x l > 0
let rec lemma heaps_mem (l: list tree)
requires { heaps l }
variant { size l }
ensures { forall x. le_roots x l -> forall y. mem y l -> le x y }
= match l with
| Nil -> ()
| Cons { children = c } r -> heaps_mem c; heaps_mem r
end
(** Binomial tree of rank `k`. *)
predicate has_order (k: int) (l: list tree) =
match l with
| Nil ->
k = 0
| Cons { rank = k'; children = c } r ->
k' = k - 1 && has_order (k-1) c && has_order (k-1) r
end
predicate binomial_tree (t: tree) =
t.rank = length t.children &&
has_order t.rank t.children
lemma has_order_length:
forall l k. has_order k l -> length l = k
(** Binomial heaps. *)
type heap = list tree
(** A heap `h` is a list of binomial trees in strict increasing order of
ranks, those ranks being no smaller than `m`. *)
predicate inv (m: int) (h: heap) =
match h with
| Nil -> true
| Cons t r -> let k = t.rank in m <= k && binomial_tree t && inv (k + 1) r
end
lemma inv_trans:
forall m1 m2 h. m1 <= m2 -> inv m2 h -> inv m1 h
let lemma inv_reverse (t: tree)
requires { binomial_tree t }
ensures { inv 0 (reverse t.children) }
= let rec aux (k: int) (l: list tree) (acc: list tree)
requires { has_order k l }
requires { inv k acc }
variant { k }
ensures { inv 0 (reverse l ++ acc) }
= match l with
| Nil -> ()
| Cons t r ->
assert { binomial_tree t };
aux (k-1) r (Cons t acc)
end in
match t with
| { rank = k; children = c } -> aux k c Nil
end
(** Heap operations. *)
let empty : heap = Nil
ensures { heaps result }
ensures { inv 0 result }
ensures { forall e. not (mem e result) }
let is_empty (h: heap) : bool
ensures { result <-> h = Nil }
= match h with Nil -> true | _ -> false end
let get_min (h: heap) : elt
requires { heaps h }
requires { h <> Nil }
ensures { mem result h }
ensures { forall x. mem x h -> le result x }
=
match h with
| Nil -> absurd
| Cons t l ->
let rec aux (m: elt) (l: list tree) : elt
requires { heaps l }
variant { l }
ensures { result = m || mem result l }
ensures { le result m }
ensures { forall x. mem x l -> le result x }
= match l with
| Nil -> m
| Cons {elem=x} r -> aux (if le x m then x else m) r
end in
aux t.elem l
end
let function link (t1 t2: tree) : tree =
if le t1.elem t2.elem then
{ elem = t1.elem; rank = t1.rank + 1; children = Cons t2 t1.children }
else
{ elem = t2.elem; rank = t2.rank + 1; children = Cons t1 t2.children }
let rec add_tree (t: tree) (h: heap)
requires { heaps (Cons t Nil) }
requires { binomial_tree t }
requires { heaps h }
requires { inv (rank t) h }
variant { h }
ensures { heaps result }
ensures { inv (rank t) result }
ensures { forall x. occ x result = occ x (Cons t Nil) + occ x h }
=
match h with
| Nil ->
Cons t Nil
| Cons hd tl ->
if rank t < rank hd then
Cons t h
else begin
assert { rank t = rank hd };
add_tree (link t hd) tl
end
end
let add (x: elt) (h: heap) : heap
requires { heaps h }
requires { inv 0 h }
ensures { heaps result }
ensures { inv 0 result }
ensures { occ x result = occ x h + 1 }
ensures { forall e. e <> x -> occ e result = occ e h }
=
add_tree { elem = x; rank = 0; children = Nil } h
let rec merge (ghost k: int) (h1 h2: heap)
requires { heaps h1 }
requires { inv k h1 }
requires { heaps h2 }
requires { inv k h2 }
variant { h1, h2 }
ensures { heaps result }
ensures { inv k result }
ensures { forall x. occ x result = occ x h1 + occ x h2 }
=
match h1, h2 with
| Nil, _ -> h2
| _, Nil -> h1
| Cons t1 tl1, Cons t2 tl2 ->
if rank t1 < rank t2 then
Cons t1 (merge (rank t1 + 1) tl1 h2)
else if rank t2 < rank t1 then
Cons t2 (merge (rank t2 + 1) h1 tl2)
else
add_tree (link t1 t2) (merge (rank t1 + 1) tl1 tl2)
end
let rec extract_min_tree (ghost k: int) (h: heap) : (tree, heap)
requires { heaps h }
requires { inv k h }
requires { h <> Nil }
variant { h }
ensures { let t, h' = result in
heaps (Cons t Nil) && heaps h' && inv k h' &&
le_roots t.elem h && binomial_tree t &&
forall x. occ x h = occ x (Cons t Nil) + occ x h' }
=
match h with
| Nil ->
absurd
| Cons t Nil ->
t, Nil
| Cons t tl ->
let t', tl' = extract_min_tree (rank t + 1) tl in
if le t.elem t'.elem then t, tl else t', Cons t tl'
end
let rec extract_min (h: heap) : (elt, heap)
requires { heaps h }
requires { inv 0 h }
requires { h <> Nil }
variant { h }
ensures { let e, h' = result in
heaps h' && inv 0 h' &&
occ e h' = occ e h - 1 &&
forall x. x <> e -> occ x h' = occ x h }
=
let t, h' = extract_min_tree 0 h in
t.elem, merge 0 (reverse t.children) h'
(** Complexity analysis. *)
use int.Power
let rec lemma has_order_size (k: int) (l: list tree)
requires { has_order k l }
variant { size l }
ensures { size l = power 2 k - 1 }
= match l with
| Nil -> ()
| Cons { children = c } r -> has_order_size (k-1) c; has_order_size (k-1) r
end
lemma binomial_tree_size:
forall t. binomial_tree t -> size t.children = power 2 t.rank - 1
let rec lemma inv_size (k: int) (l: list tree)
requires { 0 <= k }
requires { inv k l }
variant { l }
ensures { size l >= power 2 (k + length l) - power 2 k }
= match l with
| Nil -> ()
| Cons _ r -> inv_size (k+1) r
end
(** Finally we prove that the number of binomial trees is O(log n) *)
lemma heap_size:
forall h. inv 0 h -> size h >= power 2 (length h) - 1
end